How to use this calculator
- 1
Choose the phase
Select single phase (typically 120 V or 230 V for homes) or three phase (commonly 400 V or 415 V for commercial and industrial supplies).
- 2
Choose the conductor
Pick copper or aluminium. Copper has lower resistance, so it gives less voltage drop for the same size.
- 3
Enter the supply voltage
Type the voltage at your source in volts (V).
- 4
Enter the load current
Input the maximum expected current in amps (A). If you only know the wattage, use the Watts to Amps calculator first.
- 5
Enter the cable length
Enter the one-way distance from the power source to the load, in metres or feet. The formulas already account for the return path.
- 6
Select the cable size
Choose the cross-sectional area in mm². The results update instantly.
Formulas
1. R = ρ × L / A
- ρ (rho)
- 0.0175 Ω·mm²/m (Cu) / 0.0282 Ω·mm²/m (Al)
- L
- Cable Length
- A
- Cable Size (mm²)
2. Single Phase
3. Three Phase
4. Percentage Drop
Worked Example
Single phase copper
- System230 V, 20 A, single phase
- CableCopper, 50 m, 4 mm²
- Resistance0.0175 × 50 / 4 = 0.21875 Ω
- Voltage drop2 × 20 × 0.21875 = 8.75 V
- Percentage(8.75 / 230) × 100 = 3.80%
Step up to 6 mm² to bring the drop to about 2.54%.
Three phase copper
- System400 V, 50 A, three phase
- CableCopper, 100 m, 16 mm²
- Resistance0.0175 × 100 / 16 = 0.109375 Ω
- Voltage drop1.732 × 50 × 0.109375 = 9.47 V
- Percentage(9.47 / 400) × 100 = 2.37%
A 16 mm² cable is adequate for this run.
Copper vs Aluminium
| Property | Copper | Aluminium |
|---|---|---|
| Resistivity at 20°C | 0.0175 Ω·mm²/m | 0.0282 Ω·mm²/m |
| Voltage drop at same size | Lower | Higher |
| Size needed for same drop | Smaller | Substantially larger |
| Weight and cost | Heavier, usually costlier | Lighter, often cheaper |
| Connections | Standard | Requires anti-oxidant paste to prevent loosening |
Increase the cable size
A thicker cable has lower resistance, so the voltage drop falls.
Shorten the distance
Reroute the cable so the physical run is shorter.
Reduce the load
Splitting the load into several circuits lowers the current on each wire.